A mixture contains 60% water and 40% juice. How much water must be added to 50 liters of this mixture to achieve a new mixture that is 80% water?
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- Pipe A's rate = \( \frac{1}{5} \) tank/hour, Pipe B's rate = \( \frac{1}{3} \) tank/hour.
- Combined rate = \( \frac{1}{5} + \frac{1}{3} = \frac{3}{15} + \frac{5}{15} = \frac{8}{15} \) tank/hour.
- Time to fill the tank = \( \frac{1}{\frac{8}{15}} = \frac{15}{8} \) hours = 1.875 hours.
- Initial water = 60% of 50 liters = 30 liters.
- Let \( x \) be the liters of water added.
- New total volume = \( 50 + x \) liters.
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