\boxed{\frac{8}{15}}

February 22, 2026

$\boxed{\frac{8}{15}}$

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\frac{56}{120} = \frac{7}{15}
Therefore, the probability that at least one of the top 2 is selected is:
- \frac{7}{15} = \frac{8}{15}
Question: A food scientist is developing a new low-sugar snack bar and tests 10 different formulations. If she randomly selects 3 for nutritional analysis, what is the probability that at least two of them are among the top 4 most promising candidates?
We calculate the probability of selecting **exactly 2** or **exactly 3** of the top 4 formulations, and sum them.
Total number of ways to choose 3 from 10:

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